type 3 addition subtraction product on ratio & proportion Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : Two numbers whose sum is 84 can not be in the ratio

(a) 1 : 3

(b) 3 : 2

(c) 13 : 8

(d) 5 : 7

The correct answers to the above question in:

Answer: (b)

According to the question,

The number 84 must be a multiple of sum of the terms of ratio.

For ratio 3 : 2,

Sum of the terms of ratio

= 3 + 2 = 5

which is not a factor of 84.

Practice ratio & proportion (type 3 addition subtraction product on ratio & proportion) Online Quiz

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Read more addition subtraction product on ratio and proportion Based Quantitative Aptitude Questions and Answers

Question : 1

The ratio of three positive numbers is 2 : 3 : 5 and the sum of their squares is 608. The three numbers are

a) 8, 12, 20

b) 4, 6, 10

c) 10, 15, 25

d) 2, 3, 5

Answer: (a)

Numbers = 2x, 3x and 5x,

According to question,

$(2x)^2 + (3x)^2 + (5x)^2$ = 608

$4x^2 + 9x^2 + 25x^2$ = 608

$38x^2$ = 608

$x^2 = 608/38$ = 16

$x = √16$ = 4

Numbers ⇒ 2x = 2 × 4 = 8

3x = 3 × 4 = 12

5x = 5 × 4 = 20

Question : 2

The product of two positive integers is 1575 and their ratio is 9 : 7. The smaller integer is

a) 45

b) 70

c) 35

d) 25

Answer: (c)

Let the integers be 9x and 7x respectively.

According to the question,

9x × 7x = 1575

$x^2 = 1575/63$

$x^2 = 25 ⇒ x = 5

[x being positive (+ve) integer]

Smaller integer

= 7x = 7 × 5 = 35

Question : 3

The ratio of number of balls in bags x,y is 2 : 3. Five balls are taken from bag y and are dropped in bag x. Number of balls are equal in each bag now. Number of balls in each bag now is

a) 30

b) 25

c) 20

d) 45

Answer: (c)

Number of balls in bag x and y respectively

= 2a and 3a

3a - 5 = 2a + 3

a = 5 + 3 = 8

Total number of balls

= 5a = 40

Balls in each bag = 20

Question : 4

The sum of three numbers is 540. The ratio of second to third is 9 : 13 and that of first to third is 2 : 7. The third number is :

a) 250

b) 286

c) 280

d) 273

Answer: (d)

Let three numbers be a, b and c respectively.

According to the question,

a + b + c = 540

and b : c = 9 : 13

a : c = 2 : 7

$a/c × c/b = 2/7 × 13/9$

$a/b = 26/63$

b : c = 9 : 13 = 63 : 91

a : b : c = 26 : 63 : 91

Sum of the terms of ratio

= 26 + 63 + 91 = 180

c = $91/180 × 540$ = 273

Question : 5

Two numbers are in the ratio 5 : 7. On diminishing each of them by 40, they become in the ratio 17 : 27. The difference of the numbers is :

a) 137

b) 50

c) 52

d) 18

Answer: (b)

Let the two numbers are x and y.

According to the question,

$x/y = 5/7$

7x = 5y

7x - 5y = 0 ...(I)

Again, ${x - 40}/{y - 40} =17/27$

27x - 1080 = 17y - 680

27x - 17y = 1080 - 680

27x - 17y = 400 ...(II)

From (I) × 17 - (II) × 5, we have

119x-85y=0
135x-85y=2000
-+-

-16x = -2000

x = 125

Putting the value of x in equation (I)

7 × 125 = 5y

$y = {7 × 125}/5$ = 175

Difference of the numbers

= 175 - 125 = 50

Using Rule 35
Two numbers are in the ratio a:b and if x is subtracted from each number the ratio becomes c:d. The two numbers will be
= ${xa(d-c)}/{ad-bc}$ and ${xb(d-c)}/{ad-bc}$

Here, a = 5, b = 7, x = 40

c = 17, d = 27

The two numbers are

= ${xa(d-c)}/{ad-bc}$

= ${40 ×5(27 - 17)}/{5 × 27 - 7 × 17}$

= ${200 × 10}/{135 - 119}$

= $2000/16 = 500/4$

1st Number = 125

And = ${xb(d-c)}/{ad-bc}$

= ${40 ×7(27 - 17)}/{5 × 27 - 7 × 17}$

= ${280 × 10}/{135 - 119}$

= $2800/16 = 700/4$

2nd Number = 175

Their difference= 175 - 125 = 50

Question : 6

When a particular number is subtracted from each of 7, 9, 11 and 15, the resulting numbers are in proportion. The number to be subtracted is :

a) 3

b) 5

c) 2

d) 1

Answer: (a)

Let the number to be subtracted be x.

According to the question,

${7 - x}/{9 - x} ={11 - x}/{15 - x}$

Now, check through options

Clearly, putting x = 3,

Each ratio = $2/3$.

Note : Solve such questions orally by mental exercise.

Using Rule 32
Let 'x' be a number which is subtracted from a, b, c and d to make them proportional, then
x = ${ad - bc}/{(a+d) - (b+c)}$
Let 'x' be a number which is added to a, b, c and d to make them proportional, then
x = ${bc - ad}/{(a+d) - (b+c)}$
Here, a, b, c and d should always be in ascending order.

The number will be x

= ${ad - bc}/{(a+d) - (b+c)}$

= ${7 × 15 - 9 × 11}/{(7 + 15) - (9 + 11)}$

= ${105 - 99}/{22 - 20} = 6/2$ = 3

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