basic calendar problems Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 4 EXERCISES
The following question based on calendar topic of verbal reasoning
(a) 4
(b) 5
(c) 3
(d) Cannot be specified
The correct answers to the above question in:
Answer: (d)
There are months of 30, 31 and 28 days and last day of the month are Wednesday.
So, using 28 and 30 days, there are 4 Mondays.
Using 31 days, there are 5 Mondays
So, it cannot be specified.
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Read more basic calendar problems Based Verbal Reasoning Questions and Answers
Question : 1
In a month of 31 days, third Thursday falls on 16th, then what will be the last day of the month?
a) 5th Friday
b) 4th Saturday
c) 5th Wednesday
d) 5th Thursday
e) None of these
Answer »Answer: (a)
Number of days left in the month after 16th = 31 - 16 = 15
Number of odd days = 15/7 = 2 weeks + 1 odd day
Therefore, Required day = Thursday + 1 odd day = Friday
As, 16th of the month is third Thursday, the day which is two weeks after this day is fifth Thursday.
So, one day after 5th Thursday is 5th Friday.
Question : 2
The calendar for the year 2007 will be the same for the year:
a) 2014
b) 2016
c) 2017
d) 2018
Answer »Answer: (d)
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd days.
Sum = 14 odd days = 0 odd day.
Therefore, Calendar for the year 2018 will be the same as for the year 2007.
Question : 3
How many days are there in x weeks x days?
a) 7x2
b) 8x
c) 14x
d) 7
Answer »Answer: (b)
Question : 4
The day on 18.09.1977 was Sunday A couple was married on this date. How many marriage anniversaries would fall on Sunday in the next 15 yr?
a) 1
b) 2
c) 5
d) 9
Answer »Answer: (b)
1977 is an ordinary year.
We know that the calendar of an ordinary year repeats after 6 yrs or 11 yrs.
Let us check for the number of odd days in 6th and 11th years.
Year | Number of odd days |
1978 | 1 |
1979 | 1 |
1980 | 2 |
1981 | 1 |
1982 | 1 |
1983 | 1 |
1984 | 2 |
1985 | 1 |
1986 | 1 |
1987 | 1 |
1988 | 2 |
From the above table, Number of odd days from 18.09.1977 to 18.09.1983 = 7,
i.e., 0 odd days
It means that in 1983, 18th September would fall on Sunday.
From the above table, a number of odd days from 18.09.1977 to 18.09.1988 = 14
i.e., 0 odd days.
Now, it is clear that 2 marriage anniversaries would fall on Sunday in the next 15 yr.
Question : 5
Which of the following is a leap year?
a) 2800
b) 1800
c) 2600
d) 3000
e) All of these
Answer »Answer: (a)
The century year which is completely divisible by 400, is a leap year.
Thus, the year 2800 is a leap year.
GET calendar PRACTICE TEST EXERCISES
basic calendar problems
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find a day without reference day
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