basic calendar problems Detailed Explanation And More Example

Answer: (b)

1977 is an ordinary year.

We know that the calendar of an ordinary year repeats after 6 yrs or 11 yrs.

Let us check for the number of odd days in 6th and 11th years.

From the above table, Number of odd days from 18.09.1977 to 18.09.1983 = 7,

i.e., 0 odd days

It means that in 1983, 18th September would fall on Sunday.

From the above table, a number of odd days from 18.09.1977 to 18.09.1988 = 14

i.e., 0 odd days.

Now, it is clear that 2 marriage anniversaries would fall on Sunday in the next 15 yr.

Answer: (d)

There are months of 30, 31 and 28 days and last day of the month are Wednesday.

So, using 28 and 30 days, there are 4 Mondays.

Using 31 days, there are 5 Mondays

So, it cannot be specified.

Answer: (a)

Number of days left in the month after 16th = 31 - 16 = 15

Number of odd days = 15/7 = 2 weeks + 1 odd day

Therefore, Required day = Thursday + 1 odd day = Friday

As, 16th of the month is third Thursday, the day which is two weeks after this day is fifth Thursday.

So, one day after 5th Thursday is 5th Friday.