choosing odd numeral pair / group Short Notes, Methods, Tips, Tricks & Techniques to Solve Problems

Type 4: Choosing Odd Pair of Numbers or Group Out - VERBAL CLASSIFICATION

Concepts & Examples, Shortcuts, Solving Techniques, Tricks & Tips PDF

Posted By Careericons Team

Introduction & Concept for Verbal Classification Type 4 - Choosing Odd Pair of Numbers or Group Out:

This type of concept is similar to the previous topic "Type 2 - Choosing Odd Pair of Word Out". If you haven't read yet check the provided link above.

Here in this, Type 4 Classification the group is given with pair or group of numbers, then you are asked to find the common property which the pair or group of numbers has. Except, one odd numeral pair or number which does not have the common property with the others. The found pair or number will be your final answer.

In this Number Classification, you are given a pair or group of numbers in which all but one pair or number are related to each other in a certain manner, thus forming a group of pairs or numbers that have the same property. You have to identify an odd number pair or number that does not belong to any other pair group or numbers.

Note that: There is a similarity exists between a given number or group of numbers. You need to identify an odd number or a group of numbers that do not belong to a group.

The number classification ia generally based on the following similarities:

  • Square and Square root of a number,
  • Cube and Cube root of a number,
  • Even & Odd number,
  • Prime number,
  • Divisibility test of a number,
  • Sum of digits of a number etc.

Below you will see pair of numerals in a group. There are four/ five pair of numbers in each group. One numerals pair in each group is different from the rest. You must choose which is the odd numerals pair or a odd numeral.


Type 4 Classification - Verbal Reasoning
Example Questions and Answers Key PDF with Shortcuts & Tricks:

In this type of classification question, specific pairs of numerals or group of numbers are given in which all but one of the pairs of numerals or group of numbers have a specific common relationship. Then you need to understand this relationship and choose the pair where the words are related differently.

Let's see some example questions for your reference which will definitely help you to get clear about the concept.

DIRECTIONS (1 to 15):

each of the questions given below, four of the five options are alike in a certain way and so form a group. Which option does not belong to the group?

Example 1:

(a) 25 (b) 9 (c) 8 (d) 16 (e) 4

Example 2:

(a) 115 (b) 85 (c) 95 (d) 75 (e) 155

Example 3:

(a) 115 (b) 161 (c) 253 (d) 391 (e) 345

Example 4:

(a) 72 (b) 96 (c) 48 (d) 28 (e) 82

Example 5:

(a) 119 (b) 123 (c) 143 (d) 133 (e) 149

Example 6:

(a) 50 (b) 65 (c) 170 (d) 255 (e) 290

Example 7:

(a) 196 (b) 256 (c) 529 (d) 576 (e) 324

Example 8:

(a) 12, 8 (b) 6, 16 (c) 18, 6 (d) 32, 3

Example 9:

(a) 72, 60 (b) 108, 96 (c) 84, 72 (d) 60, 36

Example 10:

(a) 7, 4, 9 (b) 13, 36, 7 (c) 5, 25, 9 (d) 11, 16, 7

Example 11:

(a) 15 - 12 (b) 20 - 10 (c) 30 - 18 (d) 45 - 27

Example 12:

(a) 9611 (b) 7324 (c) 2690 (d) 1754

Example 13:

(a) 19 - 27 (b) 16 - 24 (c) 36 - 6 (d) 7 - 49

Example 14:

(a) 80 - 9 (b) 64 - 8 (c) 5, 25, 9 (d) 11, 16, 7

Example 15:

(a) 22, 4, 5 (b) 34, 4, 8 (c) 37, 4, 9 (d) 54, 4, 13

Answer Key & Explained solutions for the above questions;

  1. (c) All numbers are the square of other numbers except 8.
  2. (d) 115 = 5 × 23 ; 85 = 5 × 17;
    95 = 5 × 19; 155 = 5 × 31;
    But, 75 = 5 × 15
    One factor of 75 is not a Prime Number.
  3. (e) Except for number 345, all other numbers are products of 23 and a Prime Number.
    115 = 23 × 5; 161 = 23 × 7
    253 = 23 × 11; 391 = 23 × 17
    But 345 = 23 × 15.
    The number 15 is not a Prime Number. So, 345 is the correct answer.
  4. (e) All other numbers are multiple of 4 except 82.
  5. (e) All numbers are composite numbers except 149, which is a prime number.
  6. (d) Except 255 all other numbers are one more than a perfect square.
    $50 = (7)^2 + 1, 65 = (8)^2 + 1;$
    $170 = (13)^2 + 1, 290 = (27)^2 + 1$
    But, $255 = (16)^2 – 1$
  7. (c) Except 529, all others are perfect squares of even numbers.
    The number 529 is a perfect square of an odd number.
    196 = 14 × 14; 256 = 16 × 16; 529 = 23 × 23; 576 = 24 × 24 & 324 = 18 × 18.
  8. (c) The product in all other cases is 96.
  9. (d) The difference in all the other cases is 12.
  10. (c) $(9 – 7)^2 = 4, (13 – 7)^2 = 36, (11 – 7)^2 = 16,$ But $(9 – 5)^2 ≠ 25$
  11. (b) In all the rest pairs, the difference is divisible by 3.
  12. (b) In all other numbers, the sum of the digits is 17.
  13. (b) In all the rest groups there is no common factor of the two numbers.
  14. (a) In all other pairs, one number is the square of the other.
  15. (c) In all other groups, the first number is obtained by adding 2 to the product of the second and the third numbers.

Types of Classification - Verbal Reasoning MCQs with Practice Exercises Tests, Shortcuts PDF & Online Quiz

Types of Verbal Classification Practice Exercise Test Links Shortcuts PDF & Tricks Links Online Quiz Links
Type 1: Choose Odd Words Out
Type 2: Choose Odd Pair of Words Out
Type 3: Finding Out Odd Letters or Groups
Type 4: Choosing Odd Numeral Pair/ Group Out Already you are in this page
Type 5: Choose Odd Numeral Out

Refer: Learn & Practice Verbal Classification Reasoning MCQ Tests with Example planations. Get Classification Type 4: MCQ Exercises & Tests and Online Live Quiz.

classification MCQ QUESTION & ANSWER EXERCISE
classification Shortcuts and Techniques with Examples
verbal reasoning
57 classification based verbal reasoning choosing odd numeral pair group question answer pdf.pdf

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