Model 1 Simplification using VBODMAS Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6

Find the value of * in the following $1{2/3} ÷ {2/7} × \text"*"/7 = 1{1/4} × 2/3 ÷ {1/6}$

a) 6

b) $1/6$

c) 0.006

d) 0.6

Answer: (a)

Using Rule 1,

We have

${5/3} ÷ {2/7} × \text"*"/7 = {5/4} × 2/3 × 6$

${5/3} ÷ {2/7} × \text"*"/7 = {5 × 2 × 6}/{4 × 3}$

* = ${5 × 2 × 6 × 3 × 2 × 7}/{5 × 7 × 4 × 3} = 6$

Question : 7 [SSC CGL Prelim 2002]

Find the sum of the following : $1/9 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72$

a) $1/{2520}$

b) $1/2$

c) $1/9$

d) 0

Answer: (b)

Question : 8

If $50/\text"*" = \text"*"/{12{1/2}}$, then the value of * is :

a) 25

b) $25/2$

c) 4

d) $4/25$

Answer: (a)

Let the value of * be x.

$50/x = x/{12{1/2}}$

$50/x = {2x}/25$

$2x^2$ = 50 × 25

$x^2$ = 25 × 25 ⇒ x = 25

Question : 9

$9/20 - [1/5 + (1/4 + (5/6 - \ov{1/3 + 1/2}))]$ is equal to

a) $9/10$

b) 0

c) $9/20$

d) 1

Answer: (b)

Using Rule 1,

$9/20 - [1/5 + (1/4 + (5/6 - \ov{1/3 + 1/2}))]$

= $9/20 - [1/5 + (1/4 + (5/6 - 5/6))]$

= $9/20 - [1/5 +1/4] = 9/20 - 9/20 = 0$

Question : 10 [SSC CGL Prelim 1999]

Evaluate : ${9|3 - 5|- 5|4|÷10}/{- 3 (5) - 2 × 4 ÷ 2}$

a) $4/7$

b) $9/10$

c) – $16/19$

d) – $8/17$

Answer: (c)

? = ${9|3 - 5|- 5|4|÷10}/{- 3 (5) - 2 × 4 ÷ 2}$

= ${9 × 2 - 5 × 4 ÷ 10}/{- 15 - 8 ÷ 2}$

= ${18 - 2}/{- 19} = -16/19$

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