Simple Interest Mcq Pdf Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Question :1

What is C.I. accrued on an amount of Rs.45,000 in two years at the rate of 9 p.c.p.a?

Answer: (a)

Amt = 45000$(1 + 9/100)^2$ = 53464.5

CI = 53464.5 – 45000 = 8464.5

Question :2

Two friends A and B jointly lent out Rs. 81,600 at 4% per annum compound interest. After 2 years A gets the same amount as B gets after 3 years. The investment made by B was

Answer:(c)

Let A lent Rs. x and B lent Rs. y

Since, A and B together lent out Rs. 81600

∴ x + y = 81,600

Now, given (r) Rate = 4%

∴ 1 + r = 1 + $4/100 = 26/25$

According to the question, we have

$x/y = (26/25)^{3 – 2} = 26/25$

∴ Investment made by B = 81600 × $25/51$ = 40,000

Question :3

What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?

Answer:(a)

Let the principal be P and rate of interest be R%.

∴ Required ratio = $[({P × R × 6}/100)/({P × R × 9}/100)] = {6PR}/{9PR} = 6/9 = 2 : 3$

Question :4

How much will a sum of Rs. 12,000 deposited at a rate of 9% per annum (simple interest) for 13 years amount to?

Answer:(e)

S.I. = ${12000 × 9 × 13}/100$

= Rs. 14040

∴ Amount = 12000 + 14040

= Rs. 26040

Question :5

A person invested some amount at the rate of 12% simple interest and a certain amount at the rate of 10% simple interest. He received yearly interest of Rs. 130. But if he had interchanged the amounts invested, he would have received Rs. 4 more as interest. How much did he invest at 12% simple interest ?

Answer:(b)

Let amount invested at 12% be x and amount invested at 10% be y.

According to question

130 = ${x × 12 × 1}/100 + {y × 10 × 1}/100$

⇒ 13000 = 12x + 10 y …(1)

And 134 = ${x × 10 × 1}/100 + {y × 12 × 1}/100$

⇒ 13400 = 10x + 12y ... (2)

From equations (1) and (2)

x = 500

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