# Alligation And Mixtures Pdf Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

#### ssc chsl tier 1 2024 SYLLABUS WISE SUBJECTS MCQs

Question :1

A barrel contains a mixture of wine and water in the ratio 3: 1 . How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1 : 1 ?

According to the question,

 Wine : Water Total Initial Ratio 3 : 1 4 Final Ratio 1 : 1 2 × 2

1 unit taken out and added

Hence Required part of quantity = \$1/3\$

Alternative :

Let the quantity of liquid drawn out = x

\${3 - 3/4 x}/{1 - 1/4 x + x} = 1/1\$

12 - 3x = 4 - x + 4x

8 = 6x

x = \$4/3\$

Hence required part of quantity = \${4/3}/4 = 1/3\$

Question :2

A mixture of 80 litres of wine and water contains 60 percent wine how much water must be added to make it 50 percent wine in the new mixture?

According to the question

Given :

Mixture of wine and water = 80 liters

Initial winer concentration = 60 %

Calculations:

Amount of wine in 80 litre of mixture = 60% of 80 = 48 litres

Amount of water in 80 litre of mixture = 80 - 48 = 32 litres

Also, 50 percent wine in the new mixture means 50 percent water in the new mixture

According to the question,

32 + x = 50/100 × (80 + x)

2 (32 + x) = (80 + x)

64 + 2x = 80 + x

x = 16

∴ x = 16 litres

∴ 16 litres water must be added to make it 50 percent wine in the new mixture.

Water initial mixture pure water

Question :3

In a mixture of 25 litres, the ratio of acid to water is 4: 1. Another 3 litres of water is added to the mixture. The ratio of acid to water in the new mixture is:

According to the question,

Mixture = 25 liters

Ratio of \${Acid}/{Water} = 4/1\$ > 5 units

∴ 5 units → 25 liters

1 unit → 5 liters

∴ \${Acid}/{Water} = {4 × 5}/{1 × 5} = 20/5\$

 Acid Water Initial 20 : 5 + 3 Final Ratio 20 : 8

[5 : 2]

Question :4

In a 40 litres mixture of milk and water the ratio of milk to water is 7: 1. In order to make the ratio of milk and water 3: 1, the quantity of water (in litres) that should be added to the mixture will be

According to the question,

 Milk : Water Initial Ratio 7 × 3 : 1 × 3 Final Ratio 7 × 3 : 1 × 7

Thus, Remember, water is added, not milk, so make milk equal

24 units = 40 liters

1 Unit = \$40/24\$ liters

4 units = \$40/24 × 4\$

= \$40/6 = 24/3 = 6{2}/3\$ liters

Question :5

How many kg. of salt at 42 Paise per kg must a man mix with 25 kg of salt at 24 Paise per kg, so that he may, on selling the mixture at 40 Paise per kg. gain 25% on the outlay?

According to the question,

S.P. of the mixture = 40P per kg.

C.P. of the mixture = 40 × \$100/125\$ = 32 P per kg

Now using Alligation.

Ratio of Quantity 4 : 5

5 units → 25 kg

1 unit → 5 kg

4 units → 5 × 4 = 20 kg

∴ Salt at 42 P per kg was = 20 kg

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