numerical symbolic operations Model Questions & Answers, Practice Test for ssc cgl tier 1

Directions:

In the following questions, the symbols ©, #, *, $ and @ are used with different meanings as follows:

  • 'A ©B' means 'A is smaller than B'.
  • 'A # B' means 'A is either smaller, than or equal to B'.
  • 'A * B' means 'A is greater than B'.
  • 'A $ B' means 'A is either greater than or equal to B'.
  • 'A @ B' means 'A is neither smaller than nor greater than B'.

In each of the following questions assuming the given statements to be true, find out which of the two conclusions I and II given below them is/are definitely true.

  • Give answer (a) if only conclusion I is true.
  • Give answer (b) ifonlyconclusion II is true.
  • Give answer (c) if either conclusion I or conclusion II is true.
  • Give answer (d) if neither conclusion I nor conclusion II is true.
  • Give answer (e) if both conclusions I and II are true.
Question :16

Statements: W @ T, T ! K, K ★ F


Conclusions:
I. W ! K
II. W @ K

Answer: (a)

W @ T ⇒ W = T
T ! K ⇒ T ! K ⇒ K > F
K ★ F ⇒ K > F

Hence, W = T ≥ K > F

Conclusions :

I. W ! K ⇒ W ≥ K (True)
II. W @ K ⇒ W = K (False)

Question :17

Statements: M # R, R © J, J # H


Conclusions:
I. M # H
II. R © H

Answer: (d)

M # R ⇒ M ≤ R
R © J ⇒ R < J
J # H ⇒ J ≤ H

Hence, M ≤ R < J ≤ H

Conclusions :

I. M # H ⇒ M ≤ H (False)
II. R © H ⇒ R < H (True)

Question :18

Statements:V # S, S © L, L © J


Conclusions:
I. V © L
II. S © J

Answer: (e)

V # S ⇒ V ≤ S
S © L ⇒ S < L
L © J ⇒ L < J

Hence, V ≤ S < L < J

Conclusions :

I. V © L ⇒ V < L (True)
II. S © J ⇒ S < J (True)

Question :19

Statements:H ! F, F @ G, G ★ M


Conclusions:
I. H ★ M
II. H ★ G

Answer: (a)

H ! F ⇒ H ≥ F
F @ G ⇒ F = G
G ★ M ⇒ G > M

Hence, H ≥ F = G > M

Conclusions :

I. H ★ M ⇒ H > M (True)
II. H ★ G ⇒ H > G (False)

Question :20

Statements:R © J, J ★ T, T # L


Conclusions:
I. R @ T
II. J @ L

Answer: (c)

R © J ⇒ R < J
J ★ T ⇒ J > T
T # L ⇒ T ≤ L

Hence, R < J > T ≤ L

Conclusions :

I. R @ T ⇒ R = T (False)
II. J @ L ⇒ J = L (True)

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