Alligation And Mixtures Model Questions & Answers, Practice Test for ssc cgl tier 1 2024

Question :1

The ratio in which tea costing Rs.192 per kg is to be mixed with tea costing Rs.150 per kg so that the mixed tea, when sold for Rs.194.40 per kg. gives a profit of 20% is:

Answer: (d)

According to the question,

S.P. of mixed tea = Rs. 194.40

Profit = 20% = $1/5$ (1 → Profit, 5 → C.P.)

S.P. = 6 units

6 units = $194.40/6$ = 32.4

5 units - 5 × 32.4 = Rs. 162

By Alligation

alligations and mixtures for all competitive exams N 25a

Question :2

A 20 percent gain is made by selling the mixture of two types of ghee at Rs. 480 per kg. If the type costing 610 per kg was mixed with 126 kg of the other, how many kilograms of the former was mixed ?

Answer: (b)

We cannot determine the answer to this question as we do not know the price per kg of the other type of ghee.

Hence, we cannot find the ratio of mixing which would be required in order to move further in this question.

Question :3

In my pocket there are Rs.25 consisting of only the denominations of 20 paise and 50 paise. Thus there are total 80 coins in my pocket. The no. of coins of the denomination of 50 paise is

Answer: (d)

Go through options :

30 × 50 + 50 × 20 = 2500 paise

Alternatively :

Since the average price of a coin

= $2500/80$ = 31.25 paise

alligations-and-mixtures-for-all-competitive-exams-11-2a

So the ratio of no. of 20 paise coins to the no. of 50 paise coins

= 18.75 : 11.25

= 75 : 45 = 5 : 3

Therefore, the no. of coins of the denominations of 50 paise is 30.

Question :4

The ratio of the volumes of water and glycerine in 240cc of mixture is 1: 3. The quantity of water (in cc) that should be added to the mixture so the volumes of water and glycerine become 2: 3 is 34.

Answer: (c)

According to the question,

Mixture = 240 cc

Ratio of ${Water}/{Glycerine} = 1/3$ > 4 units

4 units → 240

1 unit → 60

Thus, ${Water}/{Glycerine} = {1 × 60}/{3 × 60} = 60/180$

Water 60 + [x] Glycerine 180 × 60

× 60 ↓ 120

Thus, 60 + x = 120

x = 60 cc

Quantity of water added = 60

Question :5

In an alloy there is 12% of copper. To get 69 kg of copper. How much alloy will be required?

Answer: (c)

According to the question,

Alloy contains 12% of copper

= $12/100 = 3/25$ (3 → Copper, 25 → Mixture)

3 kg of copper in 25 kg mixture

1 kg of copper

= $25/3$ kg mixture

69 kg of copper

= $25/9 × 69$ = 25 × 23 = 575 kg

Alloy = 575 kg

ssc cgl tier 1 2024 IMPORTANT QUESTION AND ANSWERS

Recently Added Subject & Categories For All Competitive Exams

Direction and Distance Sense Test for IBPS PO MAINS 2025

Direction and Distance Sense Test MCQ questions and easy explanation, download PDF for IBPS PO MAINS 2025. Reasoning model exercises all Competitive Exams

20-Jan-2025 by Careericons

Continue Reading »

Top 100 Ratio Proportion MCQ, PDF for IBPS PO MAINS 2025

Get answers to the Ratio Proportion MCQ questions and easy explanation, download PDF for IBPS PO MAINS 2025. Attitude model exercises all Competitive Exams

10-Jan-2025 by Careericons

Continue Reading »

Important 100+ Synonyms MCQ, PDF for IBPS PO MAINS 2025

Get answers to the Synonyms MCQ questions and easy explanation, download PDF for IBPS PO MAINS 2025. General English model exercises all Competitive Exams

09-Jan-2025 by Careericons

Continue Reading »

IBPS PO MAINS 2025: Blood Relations Reasoning MCQ, PDF

Get answers to the Blood Relations MCQ questions and easy explanation, download PDF for IBPS PO MAINS 2025. Reasoning model exercises all Competitive Exams

07-Jan-2025 by Careericons

Continue Reading »