Alligation And Mixtures Model Questions & Answers, Practice Test for ssc cgl tier 1 2024
ssc cgl tier 1 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio & Proportion
Percentage
Time & Work
Time & Distance
Trigonometric Ratios & Identities
Average
Profit & Loss
Alligation & Mixtures
Simple Interest
The ratio in which tea costing Rs.192 per kg is to be mixed with tea costing Rs.150 per kg so that the mixed tea, when sold for Rs.194.40 per kg. gives a profit of 20% is:
Answer: (d)
According to the question,
S.P. of mixed tea = Rs. 194.40
Profit = 20% = $1/5$ (1 → Profit, 5 → C.P.)
S.P. = 6 units
6 units = $194.40/6$ = 32.4
5 units - 5 × 32.4 = Rs. 162
By Alligation
A 20 percent gain is made by selling the mixture of two types of ghee at Rs. 480 per kg. If the type costing 610 per kg was mixed with 126 kg of the other, how many kilograms of the former was mixed ?
Answer: (b)
We cannot determine the answer to this question as we do not know the price per kg of the other type of ghee.
Hence, we cannot find the ratio of mixing which would be required in order to move further in this question.
In my pocket there are Rs.25 consisting of only the denominations of 20 paise and 50 paise. Thus there are total 80 coins in my pocket. The no. of coins of the denomination of 50 paise is
Answer: (d)
Go through options :
30 × 50 + 50 × 20 = 2500 paise
Alternatively :
Since the average price of a coin
= $2500/80$ = 31.25 paise
So the ratio of no. of 20 paise coins to the no. of 50 paise coins
= 18.75 : 11.25
= 75 : 45 = 5 : 3
Therefore, the no. of coins of the denominations of 50 paise is 30.
The ratio of the volumes of water and glycerine in 240cc of mixture is 1: 3. The quantity of water (in cc) that should be added to the mixture so the volumes of water and glycerine become 2: 3 is 34.
Answer: (c)
According to the question,
Mixture = 240 cc
Ratio of ${Water}/{Glycerine} = 1/3$ > 4 units
4 units → 240
1 unit → 60
Thus, ${Water}/{Glycerine} = {1 × 60}/{3 × 60} = 60/180$
Water 60 + [x] Glycerine 180 × 60
× 60 ↓ 120
Thus, 60 + x = 120
x = 60 cc
Quantity of water added = 60
In an alloy there is 12% of copper. To get 69 kg of copper. How much alloy will be required?
Answer: (c)
According to the question,
Alloy contains 12% of copper
= $12/100 = 3/25$ (3 → Copper, 25 → Mixture)
3 kg of copper in 25 kg mixture
1 kg of copper
= $25/3$ kg mixture
69 kg of copper
= $25/9 × 69$ = 25 × 23 = 575 kg
Alloy = 575 kg
ssc cgl tier 1 2024 IMPORTANT QUESTION AND ANSWERS
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SSC CGL Tier 1: Number System Questions PDF For 2024 Exam »
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SSC CGL 2024: 150+ Percentage Questions & Solved Answers »
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SSC CGL 2024 Time and Work Solved Questions & Answers PDF »
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SSC CGL 2024: Time and Distance Questions and Answers PDF »
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SSC CGL 2024: Trigonometric Ratios & Identities MCQ Test »
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Top 100 Average Aptitude MCQ Practice Exercise PDF SSC »
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100+ Profit and Loss Aptitude MCQ Practice Exercise SSC »
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Top Alligation and Mixture Practice Exercise PDF for SSC »
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