profit and loss Model Questions & Answers, Practice Test for ibps rrb po prelims
A sells a tube to B at a profit of 20% and B sells it to C at profit of 25 %. If C pays Rs. 225 for it, what did A pay for it?
Answer: (c)
Let A paid = Rs. x
125 % of 120% of x = 225
⇒ $125/100 × 120/100 × x = 225$
⇒ $x = {225 × 100 × 100}/{125 × 120}$ = Rs. 150
The cost price of a book is Rs. 150. At what price should it be sold to gain 20% ?
Answer: (c)
Rs. 150 + $20/100 × 150$ = Rs.180
S.P = Rs.180
I loss 9 per cent by selling pencils at the rate of 15 a rupee. How many for a rupee must I sell them to gain 5 per cent?
Answer: (a)
By the rule of fraction:
He purchased 15$({100 - 9}/100)$ for a rupee.
Now to gain 5%, he must sell 15$(91/100)(100/105) = 13$ for a rupee
A refrigerator and a camera were sold for Rs. 12000 each. The refrigerator was sold at a loss of 20% of the cost and the camera at a gain of 20% of the cost. The entire transaction results in which one of the following?
Answer: (a)
x + y + ${xy}/100$
= +20 - 20 - ${20 × 20}/100$ = -4%
Total selling price of a refrigerator and a camera
= 12000 + 12000 = Rs. 24000
Now, loss is 4%
CP × $96/100$ = 24000
CP = Rs. 25000
Loss amount = (25000 - 24000) = Rs. 1000
A man buys apples at a certain price per dozen and sells them at eight times that price per hundred. His gain or loss per cent is ________.
Answer: (a)
Let C.P.= Rs. $x/\text"dozen" = Rs.{100x}/12$ per hundred and SP ${8x}/\text"hundred"$
% profit = ${8x - {100x}/12}/{{100x}/12} × 100$
= ${96x - 100x}/{12 × 100x} × 100 × 12$
Rs. = - 4%
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