percentages Model Questions & Answers, Practice Test for ibps rrb po prelims

Answer: (b)

$15 - 6/5 - 60% of 8{1}/4$

= 13.8 - $60/100 × 33/4$

= 13.80 - 4.95 = 8.85

Answer: (c)

% reduction in consumption

= ${% \text"change in price"}/{100 + % \text"change in price"} × 100$

= $7/{100 + 7} % = 7/107 %$

Answer: (b)

Required answer = 460 × $280/100$ = 1288

Answer: (a)

Suppose Income of B = Rs. x

Income of A = $150/100 × x = Rs. {3x}/2$

Income of C = $120/100 × {3x}/2$

$6/5 × {3x}/2 = {9x}/5$

∴ $x + {3x}/2 + {9x}/5 = 86000$

${10x + 15x + 18x}/10 = 86000$

43x = 860000

x = 20000

So, income of C = $9/5 × 20000$ = Rs. 36000

Answer: (b)

Let the original fraction = $x/y$

According to the question,

${{300x}/100}/{{260y}/100} = 7/13$

or ${30x}/{26y} = 7/13$

∴ $x/y = 7/13 × 26/30 = 7/15$