Compound Interest Pdf Model Questions & Answers, Practice Test for ibps rrb clerk asst multipurpose mains 2024
ibps rrb clerk asst multipurpose mains 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio & Proportion
Percentage
Time & Work
Time & Distance
Average
Profit & Loss
Compound Interest
The population of towns A and B is the ratio of 1 : 4. For the next 2 years, the population of A would increase and that of B would decrease by the same percentage every year. After 2 years, their population became equal. What is the percentage change in the population?
Answer:(c)
$x(1 + r/100)^2 = 4x (1 - r/100)^2$
$(1 + r/100) = 2 (1 - r/100)$
= ${3r}/100 = 1$
r = $100/3 = 33 {1}/3 %$ =33.33%
Veena obtained an amount of Rs. 8,376 as simple interest on a certain amount at 8 p.c.p.a. after 6 years. What is the amount invested by Veena ?
Answer: (d)
Anil invested an amount for three year at a simple interest rate of 9% p.a. He got an amount of Rs. 19,050 at the end of three years. What principal amount did he invest?
Answer: (e)
Let the principal be = Rs. x
∴ Interest = (19050 – x)
Now,
Principal = ${Interest × 100}/{Time × Rate}$
⇒ x = ${(19050 - x) × 100}/{3 × 9}$
⇒ 27x = 1905000 – 100x
⇒127x =1905000
x = $1905000/127$ = Rs. 15000
The difference between C. I. (Compound Interest) and S.I. (Simple Interest) on a sum of Rs. 4,000 for 2 years at 5% p.a. payable yearly is
Answer:(b)
Required difference = ${PR^2}/(100)^2$
⇒ ${4000 × 5 × 5}/{100 × 100}$ = Rs.10
The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1260. The simple interest on the same sum for double the time at half the rate per cent per annum is
Answer:(c)
Let the sum be Rs. P. Then,
⇒ $[P(1 + 10/100)^2 - P]$ = 1260
⇒$[P(11/10)^2 - 1]$ = 1260
∴ Sum = Rs. 6000
So, S.I. = Rs. $({6000 × 4 × 5}/100)$
= Rs. 1200
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