Time And Distance Pdf Model Questions & Answers, Practice Test for ibps po prelims 2024 2025

Answer: (a)

Let the speed of the train be x km/hr and that of the car be y km/hr.

Then, $120/x + 480/y = 8$ or $1/x + 4/y = 1/15$ ...(1)

And, $200/x + 400/y = 25/3$ or $1/x + 2/y = 1/24$ ...(2)

Solving (1) and (2), we get

x = 60 and y = 80.

∴ Ratio of speeds = 60 : 80 = 3 : 4.

Answer: (a)

If you start at 12 noon, you would reach at 4 : 30 PM. You would be able to meet the train which left Mumbai at 8 AM, 9 AM, 10 AM, 11 AM, 12 Noon, 1 PM, 2 PM, 3 PM and 4 PM – a total of 9 trains.

Answer: (a)

Let total distance be d.

time taken for 60% distance = ${0.6d}/40 = {3d}/200$ h

time taken for 20% distance = ${0.2d}/30 = d/150$ h

time taken for remaining 20% distance = ${0.2d}/10 = d/50$ h

average speed = $d/{{3d}/200 + d/150 + d/50}$

= ${200 × 150 × 50}/{22500 + 10000 + 30000} = {200 × 150 × 50}/62500$

= 24 kmph

Answer: (c)

When A covers 1000 m, B covers 960 m.

Similarly, when B covers 1000 m, C covers 975 m.

∴ When B covers 960 m, C covers $975/1000 × 960$ = 936 m.

Thus, A can give a start to C by a distance

= (1000 – 936) m = 64 m.

Answer: (a)

Side of square park = $√25$ km = 5 km

Perimeter of park = 4 × 5 = 20 km

Time taken = ${20 km}/{3{km} / h}$ = 6 hours 40 minutes