Time And Distance Pdf Model Questions & Answers, Practice Test for ibps po prelims 2024 2025

Answer: (a)

Let T be the speed of train and C be the speed of car.

$120/T + 480/C = 8 ⇒ 1/T + 4/C = 1/15$ ...(1)

$200/T + 400/C - 8 + 20/60 ⇒ 1/T + 2/C = 1/24$ ...(2)

Subtracting (2) from (1)

$2/C (2 - 1) = 1/15 - 1/24$

$2/C = 1/40$ ⇒ C = 80

$1/T = 1/15 – 4/80$

$1/T = 1/60$ ⇒ T = 60

Required ratio = 60 : 80 = 3 : 4

Answer: (a)

Required distance

= $√{8^2 + 15^2}$

= $√{64 + 225}$

= $√289$ = 17 m

Answer: (b)

Given, distances are 2500 km, 1200 km and 500 km.

Given, speeds are 500 km/h, 400 km/h and 250 km/h

∴ Total time = $2500/500 + 1200/400 + 500/250$

= 5 + 3 + 2 = 10 hr.

∴ Average speed = $\text"Total distance"/\text"Total time"$

= ${2500 + 1200 + 500}/10 = 4200/10$

= 420 km/hr

Answer: (a)

Total time taken

= $(9/{9 + 6} + 9/{9 - 6})$ hour

= $(3/5 + 3)$ hours = 3 $3/5$ hours

Answer: (a)

Their relative speeds = (4.5 + 3.75) = 8.25 km/h

Distance = 726 metres = $726/1000$ = 0.726km

Required time = $0.726/8.25 × 60$ = 5.28 min