Mensuration Aptitude Mcq Pdf Model Questions & Answers, Practice Test for ibps po prelims 2024 2025

Answer: (a)

Cylinder

Radius = ${35}/2$ cm

height = 32 cm

volume = π$(rs)^2$h

Cone

Radius = $4/2$ cm

height = 7 cm

Volume = $1/3 π r^2$h

Volume of cylinder = volume of n cone

$π({32}/2)^2 32 = {nπ}/3 (2)^2 7$

n = 1050

Answer: (d)

Let BD = h cm.

In ΔABC,

BC = $√{h^2 + 16}$

In ΔBDA

AB = $√{h^2 + 81}$ ...(i)

In ΔABC

AB = $√{169 - (h^2 + 16)}$

= $√{169 – h^2 –16}$

= $√{153 – h^2}$ ...(ii)

From (i) and (ii)

$√{h^2 + 81} = √{153 - h^2}$

$h^2 + h^2 = 153 - 81$

$2h^2$ = 72

$h^2$ = 36

h = 6 cm

Answer: (c)

Let ABCD is a square that inclose a circle with center 'O'.

Diameter of the circle (EF)

= Side of the square (AB) = a (let)

According to the question,

Perimeter of square + perimeter of circle = 12 m

4 × a + π.a = 12

⇒ (4 + π) a = 12.

a = ${12}/{(4 + π)}$

Radius of the circle = $a/2 = 6/{(4 + π)}$

Answer: (a)

In ΔAOD,

tan 30° = ${OD}/{AD} = 1/√3$

⇒ OD = $1/√3$ AD

= $a/{2 √3}$ ...(i)

Now, OD is radius of circle. Therefore diagonal of square

= 2 × r

= $a/{2 √3} = a/√3$

Let side of a square = y

∴ $(a/√3)^2 = y^2 + y^2$

⇒ $a^2/3 = 2y^2$

$y^2 = a^2/6^$ = Area of square.

Answer: (c)

Given , ∠BAX = 70° and ∠BAQ = 40°

∠QAX = 70° – 40° = 30°

∴ ∠EAX = 90°

⇒ ∠EAB = 90° – 70° = 20°

Since, AQBE is a cyclic quadrilateral.

∴ ∠EAQ + ∠EBQ = 180°

⇒ ∠EBQ = 180° – 60° = 120°

But ∠EBA = 90°

∴ ∠ABQ = 120° – 90° = 30°