Quadratic Equations Mcq Model Questions & Answers, Practice Test for ibps po mains 2024 2025
ibps po mains 2024 2025 SYLLABUS WISE SUBJECTS MCQs
Number System
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The roots of the equation $2√x + 2x^{-1/2}$ = 5 can be found by solving
Answer: (a)
$2√x + 2/√x$ = 5
2x + 2 = 5$√x$
⇒ $4x^2$ + 8x + 4 = 25x
⇒ $4x^2$ – 17x + 4 = 0
The discriminant of $ax^2 - 2√{2x} + c$ = 0 with a, c are real constants is zero. The roots must be
Answer: (a)
$ax^2 - 2√{2x}$ + c = 0
$(2√2)^2$ - 4ac = 0
4ac = 8
ac = 2
c = $2/a$
Let α, β be the roots.
α + β ${2√2}/a$ , α β = $c/a = 2/a^2$
$(α – β)^2 = (α + β)^2 – 4α β$
= $8/a^2 - 8/a^2 = 0$
α = β
So, α = β = $√2/a$
Hence the roots are real and equal.
If the roots of the equation $(a^2 + b^2 ) x^2 – 2(ac + bd) x + (c^2 + d^2)$ = 0 are equal, then which of the following is true?
Answer: (b)
Solve this by assuming each option to be true and then check whether the given expression has equal roots for the option under check.
Thus, if we check for option (b).
ad = bc.
We assume a = 6, d = 4 b = 12 c = 2 (any set of values that satisfies ad = bc)
Then $(a^2 + b^2)x^2 – 2(ac + bc)x + (c^2 + d^2)$ = 0
$180x^2$ – 120x + 20 = 0
We can see that this has equal roots.
Thus, option (b) is a possible answer. The same way if we check for a, c and d we see that none of them gives us equal roots and can be rejected.
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