Practice Calendar problems - verbal reasoning Online Quiz (set-2) For All Competitive Exams

Q-1)   The year next to 1990 will have the same calendar as that of the year 1990.

(a)

(b)

(c)

(d)

Explanation:

The year 1990 has 365 days. i.e. 1 odd day,

the year 1991 has 365 days, i.e. 1 odd day,

the year 1992 has 366 days i.e. 2 odd days.

The likewise year 1993, 1994, 1995 have 1 odd day each.

The sum of odd days, so calculated from years 1990 - 95

= (1 + 1 + 2 + 1 + 1 + 1) = 7 days = 0 odd day

Hence, the year 1996 will have the same calendar as that of the year 1990.


Q-2)   If a day before yesterday was Thursday, then when will Sunday fall?

(a)

(b)

(c)

(d)

Explanation:

A day before yesterday = Thursday

Yesterday = Thursday + 1 = Friday

Today = Friday + 1 = Saturday

Therefore, Sunday = Saturday + 1 = Tomorrow


Q-3)   If the day before yesterday was Wednesday, when will Sunday be?

(a)

(b)

(c)

(d)

Explanation:

If the day before yesterday was Wednesday, then today will be Friday and the day after tomorrow will be Sunday.


Q-4)   On 8th Dec 2007, Saturday falls. What day of the week was it on 8th Dec. 2006?

(a)

(b)

(c)

(d)

Explanation:

The year 2006 is an ordinary year.

So, it has 1 odd day.

So, the day of 8th Dec 2007 will be 1 day beyond the day on 8th Dec 2006.

But, 8th Dec 2007 is Saturday.

Therefore, 8th Dec 2006 is Friday.


Q-5)   January 1, 2007, was Monday. What day of the week lies on Jan. 1, 2008?

(a)

(b)

(c)

(d)

Explanation:

The year 2007 is an ordinary year.

So, it has 1 odd day.

1st day of the year 2007 was Monday.

1st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.


Q-6)   On 8th Feb 2005 it was Tuesday. What was the day of the week on 8th Feb 2004?

(a)

(b)

(c)

(d)


Q-7)   What was the day of the week on 28th May 2006?

(a)

(b)

(c)

(d)


Q-8)   What was the day of the week on 15th August 1947?

(a)

(b)

(c)

(d)

Explanation:

Odd days in 1600 yrs = 0

Odd days in 300 yrs = 1

46 yrs = (11 leap year + 35 ordinary year)

= (11x2 + 35 x 1) = 1 odd day

∴ Odd days in 1946 yrs = (0+ 1+ 1) = 2

Month Odd days
January 3
February

0

(ordinary year) 

March 3
April 2
May 3
June 2
July 3
August 1 i.e, (15  ÷ 7)

Total  17  17 ÷ 7= remainder 3 odd days

Total odd days =2 + 3 = 5

∴ Required day = Friday


Q-9)   Subha went to watch the movie 9 days ago. She goes to watch movies only on Thursday, what is the day of the week today?

(a)

(b)

(c)

(d)

Explanation:

Day 9 days ago = Thursday

Therefore, Today = Thursday + 9

= Thursday + 7 + 2

= Thursday + 2 = Saturday


Q-10)   What was the day of the week on 15 August 1947?

(a)

(b)

(c)

(d)

Explanation:

15 August 1947 means,

1946 complete years + first 7 months up to July 1947 + 15 days of August 1947

1600 years have 0 odd days.

300 years have 1 odd day

46 years have 11 leap years and

35 ordinary years = (11 × 2) + (35 × 1)

= 22 + 35 = 57 odd days

= 8 × 7 + 1 odd days = 8 weeks + 1 odd day

Up to 1946 there are 1 + 1 = 2 odd days

January 1947 = 3 odd days

February 1947 = 0 odd days (1947 is a normal year)

March 1947 = 3 odd days

April 1947 = 2 odd days

May 1947 = 3 odd days

June 1947 = 2 odd days

July 1947 = 3 odd days

Up to 15 August = 15 odd days

Total number od odd days up to 15 August 1947

= 2 + 3 + 0 + 3 + 2 + 3 + 2 + 3 + 15

= 33 odd days.

Hence, 15th August 1947 was Friday.


Q-11)   If 1st January 2008 is Tuesday, then what day of the weeklies on 1st January 2009?

(a)

(b)

(c)

(d)

Explanation:

Since 2008 is a leap year.

In a leap year, last day = 1st day 1 + odd day

= Tuesday + 1 odd day

= Wednesday = 31st December

∴  1st January, 2009 = Wednesday + 1 odd day = Thursday


Q-12)   If 4th Saturday of a month was 22nd day, then what was the 13th day of that month?

(a)

(b)

(c)

(d)

Explanation:

4th Saturday = 22nd day

3rd Saturday = 22 - 7 = 15th day

∴ 13th day - Saturday - 2 = Thursday


Q-13)   If 15th June falls on 3 days after tomorrow which is Friday, then what day of the week will fall on the last date of the month?

(a)

(b)

(c)

(d)

Explanation:

Tomorrow = Friday

3 days after tomorrow = 15th June = Friday + 3 odd days = Monday

Days from 15th to 30th June = 15

15 ÷ 7 = 7)15(2 =>remainder 1 odd day

30th June = Monday + 1 odd day = Tuesday


Q-14)   If 27 March 1995 was a Monday, then what day of the week was 1 November 1994?

(a)

(b)

(c)

(d)

Explanation:

Here, 27th March 1995 was Monday.

Now, for calculating the total number of odd days. first, we calculate the total number of days till 1 November 1994.

∴  Number of days in March, 1995 = 27

Number of days in February 1995 = 28

Number of days in January 1995 = 31

Number of days in December 1994 = 31

Number of days in November 1994 = 29

Total number of days = 146

∴ Number of odd days = $146/7$ = 20$6/7$

So, 6 odd days

∴ On November 1, 1994 = Monday - 6

= Tuesday


Q-15)   What was the day of the week on 1st April 1901?

(a)

(b)

(c)

(d)

Explanation:

1st April 1901 means 1900 complete years + first 3 months of 1901 + 1 day of April

Number of odd days in 1600 yrs = 0

Number of odd days in 300 yrs = 1

Number of odd days in 1901 yrs

January 3
February 0
March 3
April 1

= 3 + 0 + 3 + 1 = 7

⇒ 0 odd days

Total number of odd days till 1st April 1901 = 0 + 1 + 0 = 1

So, the required day was Monday.


Q-16)   2 days before yesterday was Friday, then what day of the week will be the day after tomorrow?

(a)

(b)

(c)

(d)

Explanation:

2 days before yesterday = Friday

∴ Yesterday = Friday + 2 = Sunday

∴ Today = Sunday + 1 = Monday

∴  Day after tomorrow = Monday + 2 = Wednesday


Q-17)   If day after tomorrow is Tuesday, then what day of the week will it be on 2 days after the day after tomorrow?

(a)

(b)

(c)

(d)

Explanation:

A day after tomorrow = Tuesday

∴ Two days after the day after tomorrow = Tuesday + 2

= Thursday


Q-18)   If Thursday falls 2 days after tomorrow, then what day of the week was it on three days before yesterday?

(a)

(b)

(c)

(d)

Explanation:

Two days after tomorrow = Thursday

Tomorrow = Thursday - 2 = Tuesday

Today = Tuesday - 1 = Monday

Yesterday = Monday - 1 = Sunday

∴ 3 days before yesterday = Sunday - 3 = Thursday


Q-19)   If a day before yesterday was Tuesday, then what day of the week will it be on a day after tomorrow?

(a)

(b)

(c)

(d)

Explanation:

A day before yesterday = Tuesday

Yesterday = Tuesday + 1 = Wednesday

Today = Wednesday + 1 = Thursday

Tomorrow = Thursday + 1= Friday

∴ Day after tomorrow = Friday + 1 = Saturday


Q-20)   On which day of the week does 18th September 1991 fall?

(a)

(b)

(c)

(d)

Explanation:

18th September 1991 means,

1990 complete years + 8 months of 1991 + 18 days of September

Number of odd days in 1600 yrs = 0

Number of odd days in 300 yrs = 1

Number of odd days in 90 yrs (22 leap year + 68 ordinary years )

= 22 × 2 + 68 × 1

= 44 + 68 = 112

⇒ 0 odd days

Number of odd days in 1991,

January 3
February 0
March 3
April 2
May 3
June 2
July 3
August 3
September 4

= 3 + 0 + 3 + 2 +3 + 2 + 3 + 3 + 4

= 23 = 7 × 3 + 2

= 2 odd days

Total number of odd days till 18th September, 1991

= 0 + 1 + 0 + 2 = 3

So, the required day was Wednesday.