# Practice Calendar Problems - Verbal Reasoning Online Quiz (Set-1) For All Competitive Exams

#### Q-1) How many Monday's are there in a particular month of a particular year if the month ends on Wednesday?

(a)

(b)

(c)

(d)

**Explanation:**

There are months of 30, 31 and 28 days and last day of the month are Wednesday.

So, using 28 and 30 days, there are 4 Mondays.

Using 31 days, there are 5 Mondays

So, it cannot be specified.

#### Q-2) How many days are there in x weeks x days?

(a)

(b)

(c)

(d)

#### Q-3) Which of the following is not a leap year?

(a)

(b)

(c)

(d)

#### Q-4) Which of the following is a leap year?

(a)

(b)

(c)

(d)

(e)

**Explanation:**

The century year which is completely divisible by 400, is a leap year.

Thus, the year 2800 is a leap year.

#### Q-5) The calendar for the year 2007 will be the same for the year:

(a)

(b)

(c)

(d)

**Explanation:**

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd days.

Sum = 14 odd days = 0 odd day.

Therefore, Calendar for the year 2018 will be the same as for the year 2007.

#### Q-6) On which day of the week does 28^{th} August 2009 fall?

(a)

(b)

(c)

(d)

**Explanation:**

28^{th} August 2009 means,

2008 complete years + First 7 months of the year 2009 + 28 days of August

Number of odd days in 2000 yrs = 0

Number of odd days from 2001 yrs to 2008 yrs

Year | Number of odd days |

2001 | 1 |

2002 | 1 |

2003 | 1 |

2004 | 2 |

2005 | 1 |

2006 | 1 |

2007 | 1 |

2008 | 2 |

2001 2002 2003 2004 2005 2006 2007 2008 1 1 1 2 1 1 1 2

=1+1+1+ 2+ 1+1+1+2 = 10

= 7 x1+ 3 = 3 odd days

Number of odd days in 2009,

Month | Odd days |

January | 3 |

February |
0 (ordinary year) |

March | 3 |

April | 2 |

May | 3 |

June | 2 |

July | 3 |

August | 0 |

January February March April May July August 3 0 3 2 3 2 3 0

= 3 + 0 + 3 + 2 + 3 + 2 + 3 + 0

= 16 = 7 x 2 + 2 = 2 odd days

Total number of odd days till 28^{th} August 2009

= 0 + 3 + 2 = 5

So, the required day is Friday.

#### Q-7) The last day of a century cannot be

(a)

(b)

(c)

(d)

#### Q-8) If January 1 is a Friday, then what is the first day of the month of March in a leap year?

(a)

(b)

(c)

(d)

**Explanation:**

Total number of days from January 1 to March 1

= 30 + 29 + 1 = 60 days

(February in leap years = 29 days)

60 ÷ 7 = 8 weeks and 4 odd days

So, the fourth day from Friday = Tuesday

#### Q-9) The day before the day before yesterday is three days after Saturday. What day is it today?

(a)

(b)

(c)

(d)

**Explanation:**

Three days after Saturday is Tuesday and Tuesday is the day before a day before yesterday

So, yesterday is Thursday and today is Friday.

#### Q-10) If Tuesday falls 3 days after today, then what day of the week was it on 4 days before yesterday?

(a)

(b)

(c)

(d)

**Explanation:**

Three days after today = Tuesday

Today = Tuesday - 3 = Saturday

Yesterday = Saturday - 1 = Friday

Therefore, 4 days before yesterday = Friday - 4 = Monday

#### Q-11) If day before yesterday was Saturday, then what day of the week will it be after tomorrow?

(a)

(b)

(c)

(d)

**Explanation:**r: (d)

Day before yesterday = Saturday

Today = Saturday + 2 = Monday

Therefore, Tomorrow = Monday + 1 = Tuesday

Therefore, Day after tomorrow = Tuesday + 1 = Wednesday

#### Q-12) If 26 January 2011 was Wednesday, then what day of the week was it on 26^{th} January 2012?

(a)

(b)

(c)

(d)

**Explanation:**

26^{th} January 2011 to 26th January 2012 will be considered as an ordinary year because 26^{th} January in 2012 (a leap year) comes before 29^{th} February.

Hence, the period of this one year will have only 1 odd day.

Since 26^{th} January 2011 = Wednesday

∴ 26^{th} January 2012 = Wednesday + 1 odd day

= Thursday

#### Q-13) If 1^{st} day of a year which is not a leap year is Friday, then find the last day of that year,

(a)

(b)

(c)

(d)

**Explanation:**

As we know that, first and last day of an ordinary year is the same.

Since, 1^{st} day = Friday

⇒ Last day = Friday

#### Q-14) If it was Saturday on December 17, 1899, then what will be the day on December 22, 1901?

(a)

(b)

(c)

(d)

**Explanation:**

Since, December 17, 1899 - Saturday

December 17, 1900 - Sunday

December 18, 1901 - Tuesday

∴ December 22, 1901 - Saturday

#### Q-15) If Republic day was celebrated in 1996 on Friday, on which day in 2000 Independence day was celebrated?

(a)

(b)

(c)

(d)

**Explanation:**

Number of days in 1996 (366-26) = 340

Number of days in 1997 = 365

Number of days in 1998 = 365

Number of days in 1999 = 365

Number of days from January 2000 to July 2000 = 31 + 29 + 31 + 30 + 31 + 30 + 31

= 213

Number of days from 1^{st} to 15^{th} August, 2000 = 15

∴ Total days = 340 + 365 + 365 + 365 + 213 + 15 = 1663

∴ 1663 ÷ 7 = remainder 4

∴ 1663 days = (237 X 7 + 4) days = 237 weeks + 4 days

∴ Number of odd days = 4

∴ Day on 15^{th} August, 2000 = Friday + 4 Odd days = Tuesday

#### Q-16) If 1^{st} January 2001 was Monday, then what day of the week was it on 31^{st} December 2001?

(a)

(b)

(c)

(d)

**Explanation:**

The year 2001 was an ordinary year and in an ordinary year 1^{st} day = Last day

(remember) 1^{st} January = 31^{st} December

As, given that, 1^{st} January = Monday

Hence, 31^{st} December = Monday

#### Q-17) The first day of a leap year is Wednesday, then what day of the week was it on 31^{st} December in that year?

(a)

(b)

(c)

(d)

**Explanation:**

In a leap year, Last day = 1^{st} day + 1 odd day (remember)

As given, 1^{st} day = Wednesday

Last day = Wednesday + 1 odd day = Thursday

#### Q-18) If 1^{st} January 2007 was Monday, then what day of the weeklies on 1^{st} January 2008?

(a)

(b)

(c)

(d)

**Explanation:**

2007 is an ordinary year and in an ordinary year 1^{st} January = 31^{st} December

As, 1^{st} January = Monday

∴ 31^{st} December = Monday

∴ 1^{st} January 2008 = Monday + 1odd day = Tuesday

#### Q-19) If 15^{th} August 2011 was Tuesday, then what day of the week was it on 17^{th} September 2011?

(a)

(b)

(c)

(d)

**Explanation:**

Since Total days from 15^{th} August, 2011 to 17 September, 2011 = 33

33 ÷ 7 => 7)33(4 = remainder 5 odd days

∴ Required day = Tuesday + 5 odd days

= Sunday

#### Q-20) What was the day of the week on 28^{th} May 2006?

(a)

(b)

(c)

(d)

**Explanation:**

Odd days in 1600 yrs = 0

Odd days in 400 yrs = 0 5 yrs = (4 ordinary year + 1 leap year)

= (4 x 1+ 1 x 2) = 6 odd days

Month | Odd days |

January | 3 |

February |
0 (ordinary year) |

March | 3 |

April | 2 |

May | 0 i.e,(28 ÷ 7) |

Total | 8 |

Total odd days = 8 + 6 = 14 = 0 odd day

∴ Required day Sunday